9^2+x^2=28^2

Solution for 9^2+x^2=28^2 equation:

9^2+x^2=28^2

We move all terms to the left:

9^2+x^2-(28^2)=0

We add all the numbers together, and all the variables

x^2-703=0

a = 1; b = 0; c = -703;
Δ = b2-4ac
Δ = 02-4·1·(-703)
Δ = 2812
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2812}=\sqrt{4*703}=\sqrt{4}*\sqrt{703}=2\sqrt{703}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{703}}{2*1}=\frac{0-2\sqrt{703}}{2}
=-\frac{2\sqrt{703}}{2}
=-\sqrt{703}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{703}}{2*1}=\frac{0+2\sqrt{703}}{2}
=\frac{2\sqrt{703}}{2}
=\sqrt{703}
$